0.9x^2+5.4x+4=0

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Solution for 0.9x^2+5.4x+4=0 equation:



0.9x^2+5.4x+4=0
a = 0.9; b = 5.4; c = +4;
Δ = b2-4ac
Δ = 5.42-4·0.9·4
Δ = 14.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.4)-\sqrt{14.76}}{2*0.9}=\frac{-5.4-\sqrt{14.76}}{1.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.4)+\sqrt{14.76}}{2*0.9}=\frac{-5.4+\sqrt{14.76}}{1.8} $

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